Sunday, 11 December 2011

Re: [www.keralites.net] Solve this it is a challenge

 

Another solution is
 
a2+(axb)-a
22+(2x3)-2 =8
32+(3x7)-2=27
42+(4x5)-4=32
52+(5x8)-5=60
62+(6x7)-5=72
72+(7x8)-7=98
 
Thanks,

From: Mahi Tutu <mahi1167@yahoo.com>
To: "Keralites@yahoogroups.com" <Keralites@yahoogroups.com>
Sent: Friday, December 9, 2011 9:50 AM
Subject: Re: [www.keralites.net] Solve this it is a challenge
 
An alternate solution.....
2* 3(+1) = 8
3 * 7(+2) = 27
4 * 5(+3) = 32
5 * 8(+4) = 60
6 * 7(+5) = 72
7 * 8(+6) = 98

From: shine kumar <shinebepe@yahoo.co.in>
To: "Keralites@yahoogroups.com" <Keralites@yahoogroups.com>
Sent: Thursday, 8 December 2011 10:23 PM
Subject: Re: [www.keralites.net] Solve this it is a challenge
 
Answer is 98.

(5-1)  x 5 = 8
(10-1) x 3 = 27
(9-1)  x 4 = 32
(13-1) x 5 = 60
(13-1) x 6 = 72
(15-1) x 7 = 98

Sum of numbers minus one multiplied by the
first number.

Thanks & Regards

Shine Kumar
From: Ravi Narasimhan <ravi_narasimhan_in@yahoo.com>
To: Keralites <Keralites@yahoogroups.com>
Sent: Thursday, 8 December 2011 10:15 AM
Subject: [www.keralites.net] Solve this it is a challenge

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